Blog Assignment #2 will focus on Writing Algebraic Expressions
"Let statements" are required for this assignment!!
Blog Assignment #2:
Pretend that you are planning for a Mavericks team trip to see a play live at Trinity Rep in Providence.
An adult ticket costs $50.
A child ticket (2-14 years of age) costs $10.
1. Write an expression for the total ticket cost in dollars if a adults and 85 students attend the production.
2. Write an expression for the total ticket cost in dollars if 8 adults and S students attend the production.
Wait, we almost forgot about transportation! If we were to need 2 buses to take us to Providence it would cost $750. The transportation cost will only be shared among the students since their ticket price is less than the adults.
3. Write an expression that represents the total cost for each student. (This means one expression that includes the price of the ticket to the play and his/her share of the cost of transportation.)
4. Now that you have your algebraic expressions, what will be the total cost for each student if 85 students go on the trip?
Reminder:
In your comment remember to include the following:
* your name (first name and last initial)
* your class
* the answer to the problem – there are FOUR parts – be sure to include every part and number the expressions
* an explanation that includes the strategy you used to solve.
* is there another way to solve the problem?
* any additional thoughts you have about the problem(s)
*** Please be sure to comment on Blog Assignment #2 so that your assignment is not lost on other posts! ***
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Joseph Alden MATH 4
ReplyDeleteLet A= number of adults
Let 50A= amount of money spent on adults in dollars
Let A+85= total amount of people going to play
Let 50A+85*10= total amount of money spent for play in dollars
Let S= amount of students going to play
Let 10S=amount of money for students in dollars
Let 10S+750= amount of money spent on students and transportation in dollars
10*85+750=1600$
no i do not think that there is any other way to do this
i think that this problem was rather easy
Arielle Simard,
ReplyDeletequestion #1
If an Adult ticket coastes only $50.00 dollers
And a childes ticket only coastes $10.00 dollers, and thiers only 1 adult and thiers 85 kids you would have to multiply the $10.00 dollers with the 85 kids and get your answer for how much the whole trip coastes. and my answer was,,,,,
ANSWER:10.00 * 85 you will get $850.00 dollers in total.
ARIELLE SIMARD
ReplyDeleteif thier is 1 adult and 85 kids and the adult costes $50.00 dollers and a kid coastes 10.DOLLERS then you would have to multiply to get the answer that you want and the answer that i got waz.
ANSWER: YOU DO $10.00 * 85 * 50 FOR THE ADULT AND YOU WOULD GET 42,500.00 DOLLERS
Ben Piccolo Evans
ReplyDeleteMath 1
1)let 85*10+(50a)
2)let 8*50(10s)
3)let 1440/85=cost of the ticket
4)The cost is $26 per student
Explanation:I took 720+720=1440 and divided that by 85 kids then I added $10 to each student.
My thoughts: I think you could use this method if you were to take an airplane
Example:
2 people cost is 235+tax tax=50so 235+235=470 so you add $50 tax and the airline tickets are $520.
Devin K.
ReplyDelete1 class
a= Adults
a50+85*10= how much the cost is for everybody in dollars.
8*50+s10= how much the cost is for everybody in dollars.
S*10+t= amount for the kids plus transportation in dollars
85*10=850
$850.00
zackery primiano 1/10/10
ReplyDeletemath1
answer340
Problem #1-2-3-4
#1 A=number of adults
a50=number of adults x cost of tickets
a x 10=total cost of students and adults
#2
S=number of students
s10=number of students times the cost of a student ticket
s+10+2x750=total cost of tickets for students and shared bus fee
#3
c=shared cost renting two buses
cx5=shared cost for renting buses
c10+5=cost of ticket plus split fee for renting buses
#4
The total cost would be 340 because the cost of a student ticket is $10 the number of students going is 85 + 10 charge for ticket and number of students then add 750x2 then divide 5 by the total from 750x2 then add what you got from 85+10 and what you got from the problem and you get 340
kyle d math 2
ReplyDeletelet ax50+850= the total cost of the theater tickets for a adults and 85 kids.let sx10+400=8 adults and s kids, let s divided 750 equal the total cost of transportation costs for students.Let sdivided by (10x750)= total amount of every childs cost for the play and transportation.
85 divided by (10x750)=88 dollars and 23 cents since 85 goes into 7500 88 times and.23 times.
the proccedure is using the let sentances to organize the work so it makes it easier. then when you times the 750 and 10 you add one 0 to get 7,500 then divide that by 85 to get 88.23. this is a simple let statment and is used many times in the math text book. i belive that there is another way to solve this problem and i would want to use this strategy again in another problem.
1. Let a=number of adult going to trip
ReplyDeleteLet b=cost of one adult ticket in dollars
Let b*a=total cost of all adult tickets in dollars
Let (b*a) +10*85=cost of every on going on the trip in dollars
b=$50
2. Let s=number of students going on the trip
Let m=the cost of one students ticket in dollars
Let s*m=total cost of all students tickets in dollars
Let (s*m) +50*8=total cost of everyone going to trip in dollars
m=$10
3. If there are 85 students going to the trip that means 85 times 10 equals 850 dollars.
Also they have to pay for transportation so 750 divided by 85 equals $8.82.
$850/85=$10 Cost of ticket for one student
$750/85=$8.82 Cost of transportation for one student.
4.
($850/85=$10)+ ($750/85=$8.82)=$18.82= Total cost for trip and transportation for one student
I don’t think there is another way to solve these problems.
MoNsTeR A.K.A Garrett N. Math 4
Math: 2
ReplyDeleteAn adult ticket costs $50.
A child ticket (2-14 years of age) costs $10.
1. Write an expression for the total ticket cost in dollars if a adults and 85 students attend the production.
Let A= number of adults attending.
Let 50A= amount of money spent on ticets for adults.
85*10=850
Let 50A*850= amout of money spent total forn tickets.
An adult ticket costs $50.
A child ticket (2-14 years of age) costs $10.
2. Write an expression for the total ticket cost in dollars if 8 adults and S students attend the production.
Wait, we almost forgot about transportation! If we were to need 2 buses to take us to Providence it would cost $750. The transportation cost will only be shared among the students since their ticket price is less than the adults.
8*50=400
Let S= number of students attending.
Let 10S= ammount students pay for tickets.
Let 10S*400= total amount paid for ticets.
Let S/750= amount each student pays for the bus fare.
An adult ticket costs $50.
A child ticket (2-14 years of age) costs $10.
4. Now that you have your algebraic expressions, what will be the total cost for each student if 85 students go on the trip?
850 dollars.
connor mcmullen
ReplyDeletei have a question
are u supose to layout the question numbers like this on the page?
1.
2.
3.
4.
You may answer Blog #2 by numbering your answers to each part - I would think thatthis would help you to organize your responses as well as ensure that you answer every part. However, be sure to explain your strategy as well as make extended thoughts or connections for this problem in order to get a "2" or a "3" on the scoring rubric.
ReplyDeleteMae-Lin L. Math:2
ReplyDeleteAdult Tickets: $50
Children Tickets (2-14 yrs): $10
1)LETa= total amount of money for one adult
LETa+85= total amount of money for total people
2)LETs= total number students attending trip
LETs+8= total people attending trip
LETs+8+750= total amount or money spent total in dollars
3)LETe= price of trip for one student and their part in bus money
4) The total price for all students is $850 for the trip (total for all students together)
I have done a problem like this before in math class. I know this because we ALWAYS use LET statements
To solve this problem i used LET statements to get me through the answer to understand the problem more.
I do not think there is anothere way to solve this problem because you wouldn't know how many adults there were because in the problem it doesn't say how many adults there are.
Glenn O
ReplyDeleteMath 2
1. let C = number of children
let C * 20 = total amount spent on children
let c * 20 + 50 = the total including adults
2. let s = total amout of students
let s * 20 = total amout spent on students
8*50=total amount spent on adults
let s/750= the amount each student spends on buses
3. let s = number of students
let =total amount the kids spent on tickets
let s*20/750= the total amount each kid spends on buses
let s*20+750= total amount all kids spent
4. 85*20=1700
1700+750=2450
750/85=8
8+20=28
each student pays 28 dollars
i used a lot of let statements to help me solve this problem. I would use the same strtagy if I another problem like this. it was fun and easy to do.
Colby Ferreira
ReplyDeleteClass 4
1.
let a= the number of adults going on the trip
let a*50= the amount of money spent on all the adults in dollars
let s= 85 students
let S*10=the amount of money spent on the kids in dollars
let (a*50)+(s*10)= The amount of money spent everyone on the trip in dollars
It will cost (a*50)+(s*10)
2.
Let a= adults
Let a*50= the money spent on adults in dollars
Let s *10= the amount of money spent on kids in dollars
Let (s*10) +( a*50)+750= the total amount spent in dollars
3.
Let s= 85 kids
Let s *10+ 750 dollars= the total amount spent on kids and transportation in dollars
Let s*10+ 750 / 85= The amount of money each child spends in dollars
4.
The total cost for one person is about $18.82
I found my answer by multiplying the number of kids (85) by 10 the ticket price. I got $850 then I added that number with the transportation cost ($750) and got $1,600. Now to get the amount each person would pay you would divide it by 85 the number of students and you would get $18.82. For finding the let statement in parts 1-3 all you do is take the information they give you and like a puzzle you have to find the right numbers and variables given and put them in the order or the let statements you need to have. I would the same strategy if I was using bigger numbers like 5000 or 1000000 my strategy will still work . There is no other strategy I could find or think of in the depths of my brain that would work as easily as this one.
Tess C.
ReplyDeleteMath: 2
Let p= price altogether.
Let s= number of students altogether.
Let t= total number of tickets sold altogether.
1) 85*$10+$50=p
I got this because there are 85 students going to the play, and the coast per ticket is $10, and there is an adult going so that will coast $50 because adults are more expensive.
2)Price: 8*$50+s*$10= p
Bus: $750/s=p
I got this because 8 adults are coming, and s students which tickets will cost $10 each. the the students have to pay for the bus because the adults tickits are more expensive, so then you have to divide $750 by 2 to get the cost of the bus expence to then add the prices together.
3) S/$750+$10=p
I got this because you have to divide the number of students by how much the bus is to take plus the $10 for the ticket.
4) 85/$750+$10= $19.25
I got this because if you didvide the bus cost among 85 students and then add the answer which is $9.25 to $10 you will get $19.25 for your total cost per student
Kendra E.
ReplyDeleteMath 2
My Answers to the Problems
(I dont know how to do the dot as the multiplication sign so I'm going to use ~ )
1.
a.Let D= cost of adult ticket in dollars
b.Let C= cost of childs ticket in dollars
c.Let A= Number of adults going
d.Let C~85= Cost of all students tickets together in dollars
e. Let D~A= Cost of all adult tickets together in dollars
f. Let C~85 + D~A= total cost for all tickets in dollars
2.
a.Let S= number of students attending
b.Let D~8= cost of all adult tickets in dollars
c.Let C~S= cost of all child tickets in dollars
d.Let C~S + D~8= total cost of all tickets in dollars.
3. Let C+(750/S)= Total cost of ticket and transportation per student in dollars
4.
Let S= Number of students attending
~~~ S= 85 ~~~
Let C= Cost of one student ticket
~~~ C= $10 ~~~
$10+(750/85)
^^^^^^
~~~750/85= 8.83~~~
^
$10+(8.83)
^^^^^^^^^^
$18.83
Each Student would pay-$18.83
Explanation:
For part one, I put down the expression for the cost of each childs tickets, the cost of each adult ticket, the number of adults attending, all the students tickets together, the cost of all the adults tickets together, and the total cost.
For part two,there was a different number of students and adults going, so I put down the expressions for the number of students attending, the total cost of all the students tickets together, the cost of all the adults tickets together, and the total cost again.
For part three, I figured out the expression for the total cost per student including the transportation fees and the ticket cost. Since C=the cost of one student ticket, which is $10, and to rent two buses would be 750, and there is S number of students going, I figured out that the expression would be
~~Let C+(750/S)= Total cost per student in dollars~~
I put the (750/S) in parentheses because it would be easier to do that part first then just add the two smaller numbers rather than figure out the other part first and make it more difficult.
For part for, that was basically like the work part. I put down the answers to the expressions like...
~~Let S= number of students attending
S=85~~
~~Let C= cost of one childs ticket in dollars
C=$10~~
Then I replaced the exponents in the original expression from c+(750/s) to 10+(750/85)
After that I divided 750 by 85 which was $8.83. And after that, to check if I was correct, I multiplied 8.83 by 85 students and got $750 so then I knew I was correct.
Then I added $.8.83 to $10 for the childs ticket cost and all together it was $18.83, which is the amout each student will pay that covers the transportation and their ticket cost.
Is there any other way to solve the problem?
There may be one more way. What I tried first is, instead of finding the total cost for one student, I tried to find the total cost for all the students together. The expression was a little different-
Let C~S+(750/S)
But you still did 750/S first then after that you would multiple C~S, which was 10~85 and that was 850. Then add the two numbers together and you would get $1,733 for all the students, then you could probably divide that by the number of students to get the same answer.
I probably would have used the one I originally used instead of this one because this one takes a little longer and a little more work, and the one I originally did was a lot easier and quicker to do.
Additional Thoughts:
This problem was pretty easy to do and it was a lot different than the first blog problem we did because in the first blog post you could pick your problem out of 2 problems and it was a little shorter and only one part. With this one, you don't pick your problem and it was 4 parts so it took a little bit longer to do than the first one. It was a little difficult to figure out the expression in part 3 but once I thought about it I understood.
kellsie M
ReplyDeletemath:3
problem 2
1. LET a= the amount of adults are attending the play.
LET a50=amount it cost for adults to get in to the play
LET a50+850=amount it cost for adults and children
to find my answer i started with adults since i knew how many kids were going and the costs to go and once i figured out there were a adults i multiplyed it by 50 since thats how much the tickets cost the i added to that how much the kids total was to find the grand total
2. LET s:amout of students attended the play
LET S10=amount of money it costs for children to get in the play
LET S10+400=amount it cost for adults and children
LET s10+400+750=amount it costs for bus and tickets
i found my answer by starting with how many students were attending the play and then add how much adults and kids cost together then how much it costs for the bus ride to find that my expression would me s10+400+750. i thought it would be easier to start with children instead of adults
3.let c=how many children there are
let c/750= how mch it csts for the bus
let c/750+10=how much one student has to pay
i found my answer by starting with how many children there are for thebus because if u dont know then u wont be able to find out how much to divide 750 by.u cann start the cost they owe then add the cost u need to find but i thought it wouldd be easier if i started with wat i need to know.
4.ticket cost $10.00+4.35 for transpertation so each student has to pay $14.35 i answered this question by getting the ticket cost then it 2 buses costs 750 dollars i will divide it by 2 and divide it buy how many students thaere are and i got 85 so 375 divided by 85=4.35.i think that there are other ways to do this and i thought the way i chosee was the best for me
Angelica Vieira Math 3
ReplyDelete1)
Let T=total amount of tickets
Let AT=the cost of a adults
Let 85*10T=total cost of all students
Let T+AT+85*10T=the total cost,in dollars, for the whole production.
The process of making my strategy was I substituted the variable with the letter T. Since there was a adults attending I wrote AT to represent the total amount. The next step I indicated was since there was 85 students attending I multiplied 85 students and the cost of $10T. The last step I did was I combined all of my let statements to get this, T+AT+85*10= the total tickets cost,in dollars,for the whole production.
2)Let T= total amount of tickets
Let 8T=total cost of 8 adults
Let ST= total cost of students
Let T+8T+ST= total tickets cost,in dollars,for the whole production.
My strategy of figuring out my expression was I still kept the variable of T to represent the total amount of tickets. Next I wrote 8T for the total amount of 8 adults. After I wrote down ST to represent the total amount of students. Finally i combined all of my let statements and my expression was T+8T+ST= the total cost of the tickets,in dollars,for the whole production.
3) Let A= total amount
Let 10T= the total cost for one individual student.
Let $4.41A= the total cost each student will have to pay for the cost of a bus.
To figure out my expression I Substituted the variable with the letter A to equal the total amount. Next I did 10T to represent the cost of one student. To figure out that each student had to pay $4.41 towards the bus I used the information that two buses are $750.Then I divided those two because it would be necessary to use one bus only which would cost $375.Next i divided $375 with 85 students to get the total cost of $4.41.
4)
Let 10t= the total cost of a ticket for one student.
Let 10t+$4.41= the total cost,in dollars, each student will have to pay to get to see the play for trinity rep.
The total cost will be $14.41.
To figure out my solution my strategy was to go step by step. I started off with let statements and started to build up my work from each bit of information i read. I broke down each step and used it toward my let statements. I started with the cost of one student which was $10 and kept adding more procedures to that. Next I used the cost of the bus and broke down that information step by step and used it towards finding a solution.Finally i combined all of my expressions to find out my soultion.
I thought that this problem was challenging and really made me think and go over my information again. This situation makes you think more and its not an extreme level of difficulty but its not super easy.
Rachael.P
ReplyDeleteClass:Math.4
Answers and work:
1.)Let=(a*$50)+(85*10)
2.)Let=(8*$50)+(s*10)
3.)Let=($750/s)+10
4.)The total coast per student is
$760.00 in dollars.
Explanation:In order to solve these problems the strategy i used in the expression that was given and then read cost per tickets per adult and children. Also for the 1st problem i multiplyed the number of adults which was the letter a representing the adults then the cost per ticket then the number of children going to the trinity Rep which was 85 students and * 10 dollars per person. Same for the problem 2 but the students were s and the adults were 8.
And for 3 i did $750 for the bus and divided the number of students and plus 10.That was used in problem 4 to. The answer is $760.00.
Strategy:I am not sure there is another way to solve this problem because all you need to do is multiply or divide or add or subtract it depends on what problem it is though.
Thoughts: I really like this problem,although i don't really understand how many expresions i need to make. My Comment: I like this problem because we can practice let statements and expressions. Also it give the strategy to use.
Rhonda D
ReplyDeleteClass 4
1. Let a= amount of adults going to Trinity rep
Let a($50)+(85*10)=Total cost
2. Let S= amount of students going
Let b= cost of the bus per student
let t= total cost
let t= total cost of the tickets
Let 750/s=b
Let (b+10)s + (8*$50)=T
3. Let s= students
Let t= total cost to students
let ($750/s)+$10 *s =T
4. Let a= adults
let s= students
let b = price of bus per student
let t= total cost of trip
Let(b+$10 *s) +(a*$50)=T
Let s= 85
Let a=8
let b = $750/85
(($750/85)+10*85)+(8*$50)=T
($8.82+10*85)+(8*$50)=T
($18.82*85)+(8*$50)=T
$1599.70+400=$1999.70
T=$1999.70
I used working backwords. And there is not another way that I know of to solve this problem.
Tyler Barbosa
ReplyDeleteMath 3
1/14/09
1) let 85C= Amount of money spent for the field trip in dollars
2) S(8B)=Amount of money spent for field trip and buses in dollars
3)Let t*9= amount of money each child spent to go on the field trip in dollars.
*=multiplaction
4)The total cost of of all the childern to go on the field trip is 850 dollars
While trying to solve this problem I had used let statements to write out all the of the expressions. Then for # 4 I had multiplyed the ten dollars per ticket by the 85 children and ended up with 850 dollars.
jp hebert
ReplyDelete3
(1) (A*50)+(85*10) let-A= number of adults
(2) (8*50)+(S*10)+750 let-S= number of students
(3) 750/85=8.82 10+8.82=$18.82
(4) 18.82+400=418.82
Bobbie Diniz
ReplyDeleteMath 4
1. Let a*50 = cost of adults tickets in dollars. Let 85*10 = cost of students tickets in dollars.
I used this expression because there are 85 students and a adults. I multiplied the cost by how many people were going.
2. Let 8*50 = cost of adults tickets in dollars. Let (s*10) +750 = cost of students tickets and transportation in dollars.
I got this expression by multiplying the adults by their cost and multiplying the students by their cost. Then I added the 750 dollars for transportation
3. Let 750/s = cost in dollars for transportation of one student.
Let 750/s + 10 = total cost in dollars for one student to go to the play.
4.85*10 = 850+750 = 1600
It will cost 1600 dollars for the students to go to the play.
I do not believe there is any other way to solve this problem without using let statements because you don’t know how many students or adults there are in certain parts.
I would be willing to do this problem if the numbers were bigger because this is the fastest easiest way to do this.
Matt T.
ReplyDeleteClass 3
1. Let A= amount of adults going to the play
Let A*50= cost to take the adults to the play
Let 85*10= cost to take the students to the play
Let (A*50) + (85*10) = cost to take everyone to the play
The expression is (A*50) + 850
2. Let S= amount of students going to the play
Let S*10= cost to take the students to the play
Let 8*50= cost to take the adults to the play
Let (S*10) + (8*50) = cost to take everyone to the play
The expression is (S*10) + 400 + 750
3. The expression is 10 + (750/S)
4. 750/85 = $9 so $10 + $9 = $19
Each student will pay about $19
Lexi Winnes
ReplyDelete3 class
Part one: The expression
let a = the number of adults
let a * 50 = the total cost in dollars for the adults
let 85 = the total number of students
let 85 * 10 = the total cost in dollars for all of the students together
let (a*50) + ( 85*10) = the total cost in dollars for tickets
expression - (a*50) + (85*10)
Part Two : let s = the total number of students
let s * 10 = the total cost in dollars for the students tickets
let ( 750 / s) + ( s*10) = total cost of students tickets and transportation in dollars
let 8 *50 = total cost for adults
let ( 750/s)+ ( s*10) + (8*50) = total cost for everyone in dollars
expression: (750/2) + ( s*10) + (8*50) = total cost for everyone in dollars
Part three: let s = the number of students total
let s*10= the total cost of tickets in dollars
let 750 / s = the total cost of transportation per student in dollars
let (750/s) + (s*10) =the total cost per student in dollars
expression: (750/s) + 10s
Part four : let s = 85 students
s * 10 = 850 dollars
750 / s = 9 dollars
If there is 10 dollars fee for tickets and 9 dollars fee for transportation then the total cost per student is 19 dollars.
Answer:19 dollars per student.
I solved this problem by using let statements. I used let statements because they are very helpful when dealing with variables. By using let statements, I can form expressions using variables, then later when I figure out what the variable is equal to, I can just substitute the number for the variable without confusing myself. Another reason why I used let statements is because if we do a problem similar to this only with larger numbers, then I will have enough practice with let statements that the problem will be a little bit easier to comprehend / solve.
1.- Let 50*a+85*10= The cost to go to the production.
ReplyDelete2.- Let 8*50+S*10= The cost to go to the production.
3.- Let 10+(750/85)=The cost of one student to go to the production.
4.-The cost for each student to go on the trip is about $18. What I did to solve this is a took a paper and solved part 3. I came out with $18.
There is probably another way to solve this problem and I would do this with larger numbers, or if this problem was slightly harder. This problem was fairly easy.
Conner S. Math 1
ReplyDeletePart leta=how many people are going
let85a=how many students are going
Part2 let8s=how many students attend the play
let8s= how much it will cost for adults and students
Part3 lets+a-how much it will cost
Part4 let85s=how much it will cost for students
let85s+s=how much it will cost for students and adults together
Slade S. Math 1
ReplyDeletePart let a =how many people are going.
let 85a =how many students are going.
Part2 let8s =how many students attend the play.
let8s= how much it will cost for adults and students.
Part3 lets+a= how much it will cost.
Part4 let85s= how much it will cost for students
let85s+s= how much it will cost for students and adults together.
Amber A.
ReplyDeletemath 3
1. (85*10)+50=$900
2. let s= amount of students
let (8*50)+(10s)+750=total amount the play will cost including the transportation cost
3. 10+8.80=$18.80 total cost per student
4. If 85 students are going on this trip then it will cost $1598.00 I found my answer by looking back at problem 3. in that problem i discovered that for each student the total cost would be about $18.80 Then, I multiplied 85 by $18.80 because there were 85 students going and each must pay a total cost of $18.80 This problem can help in life when you are planning to go on a trip witha certain amount of people and a cost for each including splitting a transportation fee.
Rachel C
ReplyDeleteMath 4
Answer (s):
1: Let A50+85*10= The total ticket cost for a adults and 85 syudents
2: Let S10+8*50= The total ticket cost for S students and 8 adults
3: Let 750/S+10= Total amount S students will have to pay to go see the production
4: 750/S+10; 750/85+10
^
8.82+10
^
$18.82= The aomount each student has to pay to go to the production
EXPLAINATION: The strategy I used was to have LET statments. Also how I was able to solve the problem was checking to make sure I had more than enough information in order to have my LET statements be correct. Now to explain how I really got my answer. First I took my last let statement Let 750/S+10 and I substatuted in for the variable, basically I replaced the S with 85 because there were 85 students going on the trip to see the production. After that I divided 750 ( the cost for bus transportation) by 85 (how many students going on the trip) my answer was 8.82. taking that number I added 10 to it for how much a ticket is per student. After that I got my final answer of EACH STUDENT MUST PAY 1-$18.82 IN ORDER TO GO ON THE TRIP.
EXTRA: I do think there are others ways to do a problem like this because every person has thier own style and way of doing problems like this so therefore there are different ways of doing this. Although I do think this is the most efficent way.
THOUGHTS: I like this problem. I didn"t struggle with it but it was easily done. I thought it was perfect.
CONNECTIONS: In this problem I was sooo glad it mentiooned TRINITY because it is my second favorite theater (PPAC=#1!!! of course!) and I love it there!!! I've been there twice to see the same production: A CHRISTMAS CAROL and of course both times it was AMAZING!!!!! The first time I went was in third grade and JACOB MARELY came in from a long plank above the stage and it scared me sooo much!!! i've never seen nor done a dramatic ebnterance like that. But i hope to later in life! :)
Tyler D. class 4 1.)a(50)+85(10)
ReplyDelete2.)8(50)+S(10)+5/750
3.)10+S/750
4.)10+85/750,............10+S/750.......10+8.83=18.83 each student
my stradegey is that any number that is a varibal times it by your main number in this case for the kids 10 so a are varibale times 10
my extra thoughts are if there was a simeler problem that included bigger numbers i would not want to use my stradegey because it would be way to complacated
Austin Daniels class 2
ReplyDelete1. let a = adults 50a+10(85) =
2. let s=students 8(50)+s(10)+(750 /s)=
3. let s =students 10+(750/s)=
4.$10+($750/85)=$10+$8.83=$18.83
CB
ReplyDeleteclass 1
problem 2
answer:$2,438
part 1
Let a = the number of adults
Let 50 a = the the cost of the tickets for the adults.
Let 85 = the number of students
Let 850= the total cost of the tickets for the students
Let 50 a+ 850 = the total cost of all the tickets.
Let 860= the total cost of all the tickets.
First I did the expresion "A" for the number of adults. My next one was that I did was 50 a becuase that was the amount of money for the tickets.
Then I did the total cost of the kids tickets and got $850. Finally I added up all the remaining numbers and got $860.
Part 2
Let s + = the number of students going
let 10 s + 750 = the total amount of the ticket and the bus money in dollers
Let 8 = the number of adults
let 50+8= the total cost of the tickets for the adults
let 10s+750+58 = the total amount of everything in dollers
How I did this
first I typed down the expresion for the students and added 10.I came out 10s.Then I addes 750 for the total cost of the two busses and got 10s+750= the total amount of everything for the students
Then I did 8 + 50 for the adults added it all up and it came to 58. Finally I added up an it came to be 818 dollers alltogether.
part 3
let c = the cost of all the tickets in dollers
let 10+750c= the total cost of everything
let760=total cost of everything
The first thing that I did was the expresion, then 750 + c and the cost of the tickets for students.Lastly I added all the numbers up and got my total of 760 dollers.
part 4
my total for all the parts are $2,438 dollers in total.
All I did to figure this out was add all the totals from all the parts.
Comments and thoughts:
I thought that this problem was really hard but I took my time with all my notes and I think I got it right.
I didnt really think that there should have been so many parts becuase it might confuse some kids.
Alexia Sisson Assignment 2
ReplyDeletemath 4
1. let a=number of adults going to the play.
let 50a=cost in dollars for the adults tickets.
let 50a+85*10= cost in dollars for students and adults in dollars.
let 50a+85*10= total cost in dollars for students and adults tickets.
expresion: 50a+85*10
2.
let s= number of students going to the play.
let $750/s= bus fare for each student in dollars.
let $750/s+10s= total amount paid for students in dollars.
let $750/s+10s+8*50= amount paid for student and adults in dollars.
let $750/s+10s+8*50= total amount spent in dollars on tickets for adults and students and transpertation for students.
3.
let s= number of students going to the play.
let 750/s= cost of transpertation for each student in dollars.
let 750/s+s*10= amount spent in dollars on tickets and transpertation for each student.
expresion: 750/4s*10
4.
$750/85=$9.00 for transpertation
85*$10=$8.50 for each ticket
$9.00+$8.50= $17.50 total per student
The answer would be $17.50 per student
In this problem the strategy I used was let statments. What I did was first, I used the variable A to represent the number of adults going to the play for the 1st problem. Then, I used the let statments to make 50a an expresion to equal the cost of tickets for the adults. After, I multiplied 85 times 10 to find the amount for students. Once I did that I had my expresion. In problems 3 and 2 I used the variable S to express the number of students attending the play. I also, divided both of the s variables by 750 because that was the cost of the buses and each student had to pay for a portion of the bus total. Then, to find out the amount of money for the tickets for each student I mutiplied S times 10 because $10 is the amount for each ticket. Finally I added 750/s and 10*s and got their total spending amount in dollars. But,for problem 2 I had to add the amount for 8 adults. So I multiplied 8*50 so I added that to 750/s+10s and that was my answer for the 2nd problem. I do think there is another part you could use to answer this problem. This part would be you could use the traditional method but, I woul not use it for this problem because the variables were given to you and every part had a different question you did not need the traditional method to figure out the numbers right away. I liked this problem because I thought it was easier to understand because it was broken down into four parts because I felt it was easier to answer peice by peice to get number four to give the information you wanted.
Reid C math 3
ReplyDeletePART 1
1 adult = $50 85 children = $10
85children x $10each (85x$10)
1adult x $50each $50
$50 + 85x$10 if there are 85 children and each one is $10 a ticket then i know to multiply the # of kids by the price per kid to get how much they will all cost together. then there is an adult, which means 1 adult. 1 adult ticket is $50, so i added them to together and that made my expression. i don’t think there is any other way to solve this problem because this is a fairly easy question and this is the way i was taught to do it.
PART 2
5 ADULTS = $50 S CHILDREN = $10 TRANS. $750
5adults x $50each $250
Schildren x $10each + $750transportation (S $10 + $750)
$250 + (S $10 + $750) is how much the tickets will cost because if there are 5 adults that cost $50 each then the adults alone will cost $250. then if there are S amount of children and they each cost $10 all i can figure out is S $10. but then there is transportation which is $750. adding that information up will make an expression, which is what i did. The only other way to do this is to divide the the transportation cost among the students but either way you will get the same answer. if i did it the other way the expression would be $250 +(S $10 +$750/S x S) but that is just a very longer way of writing the same thing
PART 3
S STUDENTS = $10 TRANSPORTATION = $750 (DIVIDE AMONG STUDENTS)
1 student x $10 $10
$750 Transportation /S students ($750/S)
$10 + ($750/S) is the cost for each student. 1 student’s ticket is $10, and the $750 for transportation is divided to however many students there are, in this case there are S students, so the $750 divided by the S students is just $750/S
because i can’t do anything with the variable. again i do not see any other way of doing this problem. this reminds me of the kind of problems we did when we were first introduced to variables.
PART 4
85 STUDENTS = $10 TRANSPORTATION = $750 (ALTOGETHER)
1 student x $10 $10
$750 transportation / 85 students that it gets divided between
750/85= $8.82
$18.82 is how much each students’ cost is. the original ticket price is $10
but then the student has to pay their share of the transportation which is $8.82, so when i added the two numbers together that is my answer. These are the kind of math problems i like; multi-step and kind of hard, just something that gets your brain going, though harder problems would be great too!
Bridget O'Hanley Math:3
ReplyDelete1) let a= the number of adult tickets
let $50= the cost of one adult ticket in dollars
let a50= the cost of the adult tickets in dollars
let 85= the number of student tickets
let 10= cost of one student ticket in dollars
let 85*10=cost of the student tickets in dollars
let a50+85*10=total cost of tickets in dollars.
The total cost of tickets is;
a50+85*10
2) let 8=the number of adult tickets
let 50= cost of one adult ticket in dollars
let 8*50=cost of adult tickets in dollars
let s= the number of student ticket
let 10= the cost of one student ticket in dollars
let 10s= amount for student tickets in dollars
let 8*50+10s=the total cost for all tickets in dollars
The cost for all the tickets is;
8*50+10s
3) let 10=cost of one student ticket in dollars
let 750= cost of transportation in dollars
let 750/s= cost of transportation per student in dollars
let 10+750/s= cost per student in dollars
The cost of transportation per student is;
10+750/s
4) let 10= cost of one student ticket in dollars
let 85= number of student tickets
let 750= total cost of transportation in
dollars
let 750/85=cost of transportation per student in dollars
let 10+750/85= total cost for one student in dollars.
750/85=8.82
10+8.82=$18.82
let $18.82=total cost per student in dollars (transportation and ticket)
The total cost per student for their ticket and transportation is $18.82
-----------------------------------------------
In the first part of the problem, I used "let statements" to describe the number of adult tickets, the cost per adult ticket, the total cost of adult tickets, the number of students, the cost of one student ticket and the total cost of the student tickets. Then, I added the total cost of the adult tickets with the total cost of the student tickets to get the expression for the total cost of all the tickets.
In the second part of the problem, I also used "let statements" and here I described the number of adults, the cost of one adult ticket, the cost of all the adult tickets, the number of students, the cost of one student ticket and the total cost of "s" students. To get the expression for the total cost of S students and 8 adults, I added the total cost of student tickets with the total cost of adult tickets.
In the third part, I used "let statements" once again. These let statements described the cost of one student ticket ($10), the total cost of transportation ($750) and the cost per student for transportation ($750/s). The expression for the cost of one student is; $10 (ticket) + $750/s (transportation).
Let statements were used in the fourth part as well. These let statements had the cost of one student ticket ($10), the number of students (85), the total cost of transportation ($750) and the cost per student for transportation ($750/85=$8.82). When you add the cost of the ticket and the cost per student for transportation (10+8.82), you come up with each student paying $18.82 for the ticket and transportation.
I don't really think there is any other way to solve this problem. I think any way you do it, it will be similar to the way I did it. I liked this problem because I like using "let statements". I also like making Algebraic Expressions. I hope we continue to get more blogs like this one.
Christian Torres Class 3 1/14/10 Problem #2
ReplyDelete1. $900.00
1 x 50= 50 and 85 x 10= 850 and 850+ 50= 900.
2.$450.00
8 x 50= 400 and 10x 5 = 50 and 400 + 50= 450.
3. $200.00
5/750= 150 and 150 +50= 200 per 5 students.
4. $18.82
85 / 750 = 8.82 and 10 + 8.82= 18.82 for 85 students
Nathan P
ReplyDeleteMath3
1.(50a)+(10x85) a=number of adults times 50 because 1 adult coasts $50 then add 10x85 because the are 85 kids and each kid coasts $10.
2. (8x85)+(sx10)+(750/s)8x85+s thenadd s/750 because of transportation.
3.(sx10)+(s/750) coast of tickets then add addamount of money each student paid for tansportation.
4. (85x10)+(750/85)= $858.82
I used the stratagy of multiplying variables and then adding them. I also could have added and multiplied everything together but it was easier for me this way. :)
Connor M
ReplyDeleteclass 3
1.LET a=number of adults attending
LET 50a=cost in dollars for tickets for adults
LET 85=number of students attending
LET 10*85=cost in dollars for tickets for students
LET 50a+10*85=total
2.LET s=number of students attend
LET 10s=cost in dollars for tickets for students
LET 750/s=bus cost divided among each student
LET 10+750/s=cost in dollars pure student
LET s(10+750/s)=cost in dollars for tickets for students +bus fare
LET 8=number of adults attending
LET 50*8=cost in dollars for tickets for adults
LET50*8+10s=total ticket cost
LET 50*8+s(10+750/s)=total overall cost in dollars
3.LET c=number of students attending
LET 10c=cost in dollars for tickets for students
LET 750/c=bus cost divided among each student
LET 10+750/c= cost in dollars pure student
LET c(10+750/c)=cost in dollars for tickets for students +bus fare
4.LET 85= number of students attending
LET 85*= cost in dollars for tickets for students
LET 750/85= bus cost divided among each student
LET 10+750/85= cost in dollars pure student
LET 85(10+750/85)=cost in dollars for tickets for students +bus fare
750/85=8.82
8.82+10=18.82
18.82*85=1599.7
total cost $1599.7
I don't think there's any other way to do this because it said you had to use LET statements and thats what I did.
Gian M
ReplyDeleteMath 4
#1 A* 50 eaquals how much all adults would pay
and 85 times 10 would be how much all the childrens would equal to.
#2 8*50 eaquals hom much the adults would pay altogether and s*10 eaquals how much all children would pay altogether plus the 750 dollars the children have to pay for transportation.
#3 fisrt there are 85 students so you would have to divide 750 by 85 and get about 9 dollars plus the 10 dollars for each ticket.
#4 So each child would have to pay 19 dollars for the whole trip.
The sratergy i used was to put the expresions into the right form and then add the money for each child plus transportation.
I think this would be the easiest way to solve this problem.
Jessica S.
ReplyDeleteMath: 1
1.Let a = number of adults that go on a trip.
Let 85a = total number of people who go on a trip.
85*10 =850 = total cost for students
2. Let s = number of students who attend the production
Let 8s = total number of people who attend the production
8*50= 400= total cost for adults.
3.Let s = amount of students who go to the production
Let 10s = cost students pay to go to production
Let 10s+9 = total amount paid for trip and for transportation.
4.The total cost would be 859 which they will have extra money left.
Explanation: I looked in my notes notebook and checked for many examples. I also multiplied the amount of people to the cost of the trip and found the answers.
No there is not another way to solve this problem.
Thoughts or Connections: I thought this was kind of hard on some parts I mostly had trouble on what they had to pay for transportation.
Aidan V
ReplyDeleteClass 3
*=multiplication
1. let a=adults
let 50=amount of money in dollars for each adult
let 10=amount of money in dollars for each student
let 85=number of students going on the trip
let 85*10+a*50 = total amount of money
answer: 85*10+a*50. i dicovered this by writing out let statements. i then wrote out the expression of the total amount of money. i believe that there are other ways of solving this problem by using different let statements.
2.let s=number of students going on the trip
let 8=number of adults going on the trip
let 50=amount of money in dollars for each adult
let 10=amount of money in dollars for each student
let 750=amount of money in dollars for the buses
let 10*s=amount of money in dollars for each student
let 8*50=amount of money in dollars for each adult
let (10*s)/750+(8*50)=total amount of money in dollars
answer (10*s)/750+(8*50). i dicovered this by writing out let statements. i then wrote the expression of the total amount of money. i think that there are other ways of finding the expression if you use different let statements
3. let 85=number of students going on the trip
let 10=amount of money in dollars for each student
let 750=amount of money in dollars for the buses
let 10+750/85=total cost for one student
answer 10+750/85. i got this by using my let statements. my answer works because 750/85 is the amount of money that student has to pay for the bus ride. And then you add the price of the ticket to the busride. i do not believe that there is another way of solving this problem.
4. let 10=amount of money in dollars for each student
let 750=amount of money in dollars for the buses
let 10+(750/85)=total cost for one student
750/85=8.82or about 9 $10+$9= $19. so the total cost of the trip for one student is $19. this works because 750/85 is cost the bus ride for one student. if you add the cost of the ticket, $10, you come up with about $19. this problem was more difficult than i expected but not overwhelming. it took me longer than i would have expected. i believe that i have made an effevtive way of solving this problem but someone else could have done it differently and still have gotten the same answer.
Frank V
ReplyDeleteMath Class 3
problem 2
answer 1. a X 50 + 85 x 10. I got my answer because I knew that there were a adults and each adult cost $50 so it would be a x 50. Then because there are 85 kids and each one costs $10 it would be 85 x 10. Since they're all going together you would add the two and it would become a x 50 + 85 x 10. there are no other ways to solve this problem because you're making expressions out of the numbers so any other way would be wrong.
answer 2. 8 x 50 + s x 10 + 750. I got my answer because I knew that there were 8 adults and s students and each adult cost $50 and each kid costs $10 then you have to add the cost of the transportation which is $750, the expression would be 8 x 50 + s x 10 + 750. there are no other ways to solve this problem because you're doing the same thing as problem 1 so anything else would be wrong.
answer 3. s x $10 + $750. I got my answer because I knew that there were s kids and they each cost $10 so you would put s x $10 and then you have to add the transportation so you would then put s x $10 + $750.there are no other ways to solve this problem because you are doing the same thing as the previous two questions.
answer 4. the total cost of 85 students would be $850. I got my answer because I used the lattice method and multiplied 85 by 10 since there are 85 students and each student cost $10 and my answer was $850. Yes there are other ways to solve this problem because I used the lattice method and someone else could've used the traditional method or any other method they know.
Quinlin Preston Math 3
ReplyDelete1. the answer is: a + 8 * 10
2. the total ticket cost expression is: s = 8 * 50
the total cost is:s = 8 * 50 + 750
3. the answer is : (750 / s) + 10
4. the answer is: 750 / 85 = 8.82 8.82 + 10 + 18.82 the answer is: $18.82
I don't think that there is another way to solve this problem. The strategy that i used is just : use the LET statements and write dwn what they told me to do. I thought that the problems actually got easier because they just built off one another. The hardest part was just figuring out the first two prts variables. After that it was easy.